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BTUs per Pound-°F to Joules per Kilogram-Kelvin Converter

Enter the specific heat capacity in btus per pound-°f below to convert it to joules per kilogram-kelvin.

Convert BTUs per Pound-°F to Joules per Kilogram-Kelvin

Enter a value in btus per pound-°f (BTU/(lb·°F)) to convert to joules per kilogram-kelvin (J/(kg·K)).

Result
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20,934joules per kilogram-kelvin
5 BTU/(lb·°F) = 20,934 J/(kg·K)
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Reference:NIST OWM (SI Units — Length)
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BTU per Pound-°F to Joule per Kilogram-Kelvin Conversion Table

Table showing various btu per pound-°f measurements converted to joules per kilogram-kelvin. Click any preset value or arrow to load it into the converter.

BTUs per Pound-°F (BTU/(lb·°F))Joules per Kilogram-Kelvin (J/(kg·K))
1 BTU/(lb·°F)4,186.8 J/(kg·K)
2 BTU/(lb·°F)8,373.6 J/(kg·K)
2.5 BTU/(lb·°F)10,467 J/(kg·K)
5 BTU/(lb·°F)20,934 J/(kg·K)
10 BTU/(lb·°F)41,868 J/(kg·K)
15 BTU/(lb·°F)62,802 J/(kg·K)
20 BTU/(lb·°F)83,736 J/(kg·K)
25 BTU/(lb·°F)104,670 J/(kg·K)
30 BTU/(lb·°F)125,604 J/(kg·K)
50 BTU/(lb·°F)209,340 J/(kg·K)

How to Convert BTUs per Pound-°F to Joules per Kilogram-Kelvin

To convert btus per pound-°f to joules per kilogram-kelvin, multiply the specific heat capacity by the following conversion ratio: 4,186.8 joules per kilogram-kelvin/btu per pound-°f.

Since one btu per pound-°f is equal to 4,186.8 joules per kilogram-kelvin, you can use this simple formula to convert:

joules per kilogram-kelvin = btus per pound-°f × 4,186.8

The specific heat capacity in joules per kilogram-kelvin is equal to the specific heat capacity in btus per pound-°f multiplied by 4,186.8.

For example, here's how to convert 5 btus per pound-°f to joules per kilogram-kelvin using the formula above.

joules per kilogram-kelvin = (5 BTU/(lb·°F) × 4,186.8) = 20,934 J/(kg·K)

How Many Joules per Kilogram-Kelvin Are in a BTU per Pound-°F?

There are 4,186.8 joules per kilogram-kelvin in a btu per pound-°f, which is why we use this value in the formula above.

1 BTU/(lb·°F) = 4,186.8 J/(kg·K)|1 J/(kg·K) = 0.000238846 BTU/(lb·°F)

Our btu per pound-°f to joule per kilogram-kelvin calculator automatically converts your specific heat capacity measurements with full decimal and scientific precision across US customary, imperial, and SI metric standards.

BTUs per Pound-°F and joules per kilogram-kelvin are both units used to measure specific heat capacity. Keep reading to learn more about each unit.

What Is a BTU per Pound-°F?

A btu per pound-°f is a unit of specific heat capacity equal to 4,186.8 joules per kilogram-kelvin (J/(kg·K)), the base unit for specific heat capacity. Imperial/US specific heat capacity unit (4,186.8 J/(kg·K)). [1]

The btu per pound-°f is classified as a US customary unit of specific heat capacity. BTUs per Pound-°F can be abbreviated as BTU/(lb·°F); for example, 1 btu per pound-°f can be written as 1 BTU/(lb·°F).

When working with btus per pound-°f (BTU/(lb·°F)) in formulas or technical specifications, always verify whether your target system uses SI metric, US customary, or British imperial standards.

In practice, btus per pound-°f (BTU/(lb·°F)) are widely used across large-scale industrial, bulk, and macro-level specific heat capacity specifications within US customary workflows, engineering documentation, and technical data sheets.

What Is a Joule per Kilogram-Kelvin?

Coherent SI unit of specific heat capacity. It serves as a primary reference unit for measuring specific heat capacity across scientific and practical applications. [2]

The joule per kilogram-kelvin is classified as an International System of Units (SI) unit of specific heat capacity. Joules per Kilogram-Kelvin can be abbreviated as J/(kg·K); for example, 1 joule per kilogram-kelvin can be written as 1 J/(kg·K).

As the primary coherent reference unit for specific heat capacity in this category, all other specific heat capacity units are mathematically anchored to the joule per kilogram-kelvin (J/(kg·K)).

In practice, joules per kilogram-kelvin (J/(kg·K)) are widely used across standard specific heat capacity applications within International System of Units (SI) workflows, engineering documentation, and technical data sheets.

When converting specific heat capacity between btus per pound-°f (BTU/(lb·°F)) and joules per kilogram-kelvin (J/(kg·K)), keep full floating-point precision (1 BTU/(lb·°F) = 4,186.8 J/(kg·K); 1 J/(kg·K) = 0.000238846 BTU/(lb·°F)) during intermediate calculations and round only the final joule per kilogram-kelvin figure to match your instrument tolerance.

More BTU per Pound-°F & Joule per Kilogram-Kelvin Conversions

Need to calculate in the opposite direction? Use our joules per kilogram-kelvin to btus per pound-°f calculator to switch your starting unit immediately. You can also explore related tools such as converting joules per kilogram-kelvin to btus per pound-°f, converting kilojoules per kilogram-kelvin to joules per kilogram-kelvin, or converting joules per gram-°c to joules per kilogram-kelvin.

Frequently Asked Questions

There are 4,186.8 joules per kilogram-kelvin (J/(kg·K)) in 1 btu per pound-°f (BTU/(lb·°F)). Conversely, 1 joule per kilogram-kelvin (J/(kg·K)) is equal to 0.00023884 btus per pound-°f (BTU/(lb·°F)).

References

NIST · BIPM · ISO
  1. [1]
    NIST OWM (SI Units — Length)·Specific Heat Capacity Metrology Standard — BTUs per Pound-°F (BTU/(lb·°F)) to Joules per Kilogram-Kelvin (J/(kg·K))
    NIST OWM Standard
  2. [2]
    BIPM (SI Base Unit: Metre (m))·Unit Specifications: BTU per Pound-°F (BTU/(lb·°F)) & Joule per Kilogram-Kelvin (J/(kg·K))
    BIPM Specification
  3. [3]
    NIST HB 133 (NIST Handbook 133 (2019 Ed.))·Conversion Factors & Mathematical Basis (BTU/(lb·°F) to J/(kg·K))
    NIST HB 133 Reference
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